Saturday, September 29, 2001 |
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"GRANDPA, please tell me a story." "Dear child, I am old, so, I don't remember any story now," "My friend’s Grandpa is old as well, then, how does he remember so many stories?" "All right, what story would you like to hear?" "Father says that you participated in a great race once. Tell me about it?" "Yes… they called it a great race of the great Olympics. Your grandpa wasn't an old man then. He was the best runner in the country, but no matter how good you are, there is always someone who is better than you. Your grandfather, too, had such a competitor, fierce as a lion and good as a saint. The final race had a photo finish and even the camera could not tell who had won between your Grandpa and his rival, so, it was announced that there would be a challenge race to decide the winner." "One thing more,
dear child. Your grandpa wasn't a rich man then, but so was his worthy
rival. Your father was a little boy then and so sick that only an
expensive treatment in a foreign land could save his life… and the
government had announced a huge reward for the winner of the race. This
money could save your father's life, but I had no energy left for
another race and my rival knew it. I was like a cheetah, quick in a
short dash, but low on stamina for a long race, while he was like a
Siberian crane, fast and untiring. As tears washed my cheeks, he came to
me with an offer that I could not refuse; he called it a challenge,
where he would run three laps, while I ran two." |
"Well, I don't remember, but let X
be the distance around the track (in yards), A be the rival's speed in
the first race and B be Grandpa's speed in the first race. Since both
runners stopped running at the same time, the distance they travelled
divided by their speed will be equal, generating the following two
equations: First race: (2*x+150)/A=(2*x)/B; second race:
(4*x)/((4/3)*A)=x/((9/8)*B)+x/B+(x-180)/((9/10)*B). Looking at the
first-race equation, it is evident that if you can express Grandpa's
speed in terms of a ratio to the rival's speed, the lap size will fall
out of the equation. To do this, we must remove the lap distance X from
the picture. We solve each equation for X in terms of A and B. On one
hand, X equals -150/[A*{ (2/A)-(2/B)} ] and on the other hand, X equals
-200/[B*{ (3/A)-(3/B)} ]. Remove X and set the two equations equal to
each other: -150/[A*{ (2/A)-(2/B)} ]= -200/[B*{ (3/A)-(3/B)} ]. Solving
for B, we get B=(8/9)*A. Substituting this into either of the initial
equations, we get (2X+150)/A=2X/[(8/9)*A]. Solving for X, we get X=600
yards." |